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What is the output of the following fragment? please explain. C language int i = 1;...

What is the output of the following fragment?

please explain.

C language
int i = 1;
int j = 1;
while (i < 5) {
i++;
j = j * 2;
}
printf(“%d”, j);
(a) 4
(b) 8
(c) 16
(d) 32

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Answer #1 

int i = 1;
int j = 1;
while (i < 5) {
    i++;
    j = j * 2;
}
printf(“%d”, j);


Let's trace through all iterations of while loop
i = 1
    i is increased to 2
    j = j*2 = 1*2 = 2
i = 2
    i is increased to 3
    j = j*2 = 2*2 = 4
i = 3
    i is increased to 4
    j = j*2 = 4*2 = 8
i = 4
    i is increased to 5
    j = j*2 = 8*2 = 16
i = 5
    loop exits because i < 5 is false.
so, final value of j is 16
so, it prints 16

Answer: (c) 16


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