What is the redox reaction between these three equations:
1. NaOCl + 2HCl --> NaCl + H2O + Cl2
2. Cl2 + 2I- --> I2 + 2Cl-
3. 2S2O3^2- + I2 --> S4O6^2- + 2I-
answer : two redox reaction are here
Cl2 + 2I- --> I2 + 2Cl-
2S2O3^2- + I2 --> S4O6^2- + 2I-
explanation:
reason: Cl2 ----------------> Cl-
Cl oxidation state changes from 0 to -1 . so it is reduction
I- -----------------> I2
here I oxidation state changes from -1 to 0 . so it is oxidation .
both oxidation and reduction reaction takes place .it is redox reaction
2S2O3^2- + I2 --> S4O6^2- + 2I- . this is also redox reaction . because
S oxidation state changes from 2.0 to 2.5 it is oxidation
I oxidation state changes from 0 to -1 .it is reduction .so it is also redox reaction
but in the queston
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equations that may be useful are:
2I(-)+SO2O8(2-)->I2+2SO4(2-)
and
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