A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 42.5 mL of 0.0700 M...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 42.5 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 16.8 mL of 0.0120 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN–. Titration of the newly freed EDTA required 26.9 mL of 0.0120 M Ca2+. What were the molarities of Cd2+ and Mn2+ in the original solution?
Answer: ([Cd2+] = 0.00646 M; and [Mn2+] = 0.0490 M)
The answer is here, just help me show work so I can learn please
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A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 42.5
mL of 0.0700 M...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.6 mL of 0.0150 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN“. Titration of the newly freed EDTA required 11.3 mL of 0.0150 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? concentration: M Mn2+ concentration: M Cd2+
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7 mL of 0.0500M EDTA....
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7
mL of 0.0500M EDTA. Titration of the excess unreacted EDTA required
15.8 mL of 0.0190 M Ca2+. The Cd2+ was displaced from EDTA by the
addition of an excess of CN−. Titration of the newly freed EDTA
required 13.7 mL of 0.0190 M Ca2+. What are the concentrations of
Cd2+ and Mn2+ in the original solution?
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7...
A 50.0 mL sample containing Cd²+ and Mn + was treated with 43.8 mL of 0.0700 M EDTA. Titration of the excess unreac...
A 50.0 mL sample containing Cd²+ and Mn + was treated with 43.8 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.4 mL of 0.0320 M Ca2+ The Cd2+ was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 28.2 mL of 0.0320 M Capt. What are the concentrations of Cd- and Mn in the original solution? concentration: M Mn+ concentration: M Cd2+
A sample containing Cd2+ and Mn2+ was treated with 60.1 ml of 0.0400M EDTA. Titration of...
A sample containing Cd2+ and Mn2+ was treated with 60.1 ml of 0.0400M EDTA. Titration of the excess unreacted EDTA required 16.8ml of 0.013M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN-. Titration of the newly freed EDTA required 10.4ml of 0.013M Ca2=. What are the concentrations of Cd2+ and Mn2+ in the original solution?
Please help! Will rate. A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5...
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2...
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2 and then, Ca2* was titrated at pH 13 with 9.25 ml of the same EDTA solution. Calculate ppm CaCo, (FW-100.09) and MgCO, (FW-84.31) in the sample. FWca: 40.08; FWm: 24.30
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10....
A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 17.03 mL of...
A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 17.03 mL of 0.04947 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F- to mask the A13+. To the 50.00 mL sample, 25.00 mL of 0.04947 M EDTA was added. The excess EDTA was then titrated with 0.02164 M Mn2+. A total of 25.3 mL was required to reach the methylthymol blue end point. Determine pA13+ and...
6. (8) A 50.0 mL sample of hard water containing Ca2 was titrated with 0.0500 M...
6. (8) A 50.0 mL sample of hard water containing Ca2 was titrated with 0.0500 M EDTA standard solution at pH 10 and with Eriochrome Black T indicator. The endpoint was reached when 11.35 mL of EDTA was added a) (6) Calculate the concentration of Ca* in the unknown sample in moles per liter (M). b) (2) What is the pCa of the solution?
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of a 0.04328 M EDTA solution. The solution is then back titrated with 0.02246 M Zn2 solution at a pH of 5. A volume of 21.60 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and Ni2 solution is fed through an ion-exchange column that retains Ni2 . The Cu2 that passed through the...
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 57.2 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.6 mL of 0.0150 M Ca2+. The Cd2+ was displaced from EDTA by the addition of an excess of CN“. Titration of the newly freed EDTA required 11.3 mL of 0.0150 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? concentration: M Mn2+ concentration: M Cd2+
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7
mL of 0.0500M EDTA. Titration of the excess unreacted EDTA required
15.8 mL of 0.0190 M Ca2+. The Cd2+ was displaced from EDTA by the
addition of an excess of CN−. Titration of the newly freed EDTA
required 13.7 mL of 0.0190 M Ca2+. What are the concentrations of
Cd2+ and Mn2+ in the original solution?
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 51.7...
A 50.0 mL sample containing Cd²+ and Mn + was treated with 43.8 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 14.4 mL of 0.0320 M Ca2+ The Cd2+ was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 28.2 mL of 0.0320 M Capt. What are the concentrations of Cd- and Mn in the original solution? concentration: M Mn+ concentration: M Cd2+
Please help! Will rate.
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.5 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 13.3 mL of 0.0100 M Ca. The Cd2t was displaced from EDTA by the addition of an excess of CN. Titration of the newly freed EDTA required 11.2 mL of 0.0100 M Ca2+. What are the concentrations of Cd2+ and Mn2+ in the original solution? M Mn2+ concentration: M Cd2 concentration: A...
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10. A 50.0 mL sample of water containing both Ca? and Mg is titrated in another 50.0 mL sample, the Mg* was precipitated as Mg(OH)2 and then, Ca2* was titrated at pH 13 with 9.25 ml of the same EDTA solution. Calculate ppm CaCo, (FW-100.09) and MgCO, (FW-84.31) in the sample. FWca: 40.08; FWm: 24.30
Problem 4: EDTA titration with 16.55 ml of o.0114 M EDTA at pH-10....
A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 17.03 mL of 0.04947 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F- to mask the A13+. To the 50.00 mL sample, 25.00 mL of 0.04947 M EDTA was added. The excess EDTA was then titrated with 0.02164 M Mn2+. A total of 25.3 mL was required to reach the methylthymol blue end point. Determine pA13+ and...
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