The reaction below forms the molecule CHFClBr starting from atoms of the elements. C + H + F + Cl + Br → CHFClBr Given the change of energy of this reaction is ∆E= -1502 kJ and the average bond energies (in kJ/mol) C—H (413), C—Br (276), and C—Cl (328), what is the calculated value for the the C—F bond energy? Blank 1 kJ/mol Hint: (1) This question asks you to think about solving "backwards" from the way most of the other questions in this PiQ are phrased.
Delta E(rxn) = 0 - [H(C-H) + H(C-Cl) + H(C-F) + H(C-Br)]
-1502 = -(413 + 328 + x + 276)
1502 = 1017 + x
x = 485 KJ/mol .... Answer
The reaction below forms the molecule CHFClBr starting from atoms of the elements. C + H...
Using the table of bond energies below, the delta H for the reaction is? H2C = CH2 + H-Br -> H3C - CH2Br This is ethylene plus hydrogen going to ethyl bromide. Bond C-C C = C C - H H - Br C - Br D (kj/mol) 348 614 413 366 276 SHOW WORK
2. Consider the gas phase combustion of that molecule: C,Hon + OzoラCoan + H2Ow. A. Calculate the energy needed to break all the bonds in 1 mole of propene, CaHe TABLE 9.4 Bond Energies (kJ/mol)* Single Bonds C-H 414 N-H 389 -H 6 F-F 159 C-C 348 N-N 163 o-o 146 C-F 253 C-N 293 N-o 201-F 19 C-c 242 C-o 351N-F 272 -C 203 r-F 287 C-F 439 N-CI 200 o-1 234 Br-Cl 218 C-Cl 328 N-Br 243 C-Br...
Using the table of average bond energies below, the AH for the reaction is k], C=0(g) + 2H2(g) → H3C-0-Hg) Bond: C-0 C=0 C=0 D(kJ/mol): 358 799 1072 C-H 413 H-H 436 O-H 463 -116 -276 +116 +276
Problem 5.83 Use bond enthalpies in the table below to estimate ?H for each of the following reactions. Problem 5.83 Part A Use bond enthalpies in the table below to estimate ? 1 for each of the following reactions H-H(g) + Br-Br(g) ? 2H-Br(g) Express your answer in kilojoules to 3 significant figures Average Bond Enthalpies (kJ/mol) 103 kJ C-H 413 N-H 391 O-H 463 F-F 155 C-C 348 N-N 163 O-O 146 C-C 614 N-O 201 O O 495...
• Bond Br-Br CEC C-C C-Br C-H Use the bond energies provided to estimate AHørxn for the reaction below. H-CEC-H 2 Br2() + C2H2(g) → C2H2Br4(1) AH®rxn = ? Bond Energy (kJ/mol) Break (+) Make (-) 193 2 Br-Br ICEC 837 ICEC 26-H 347 276 2C-H 4 Br-Br 414
Please show work! I've tried this problem a few times, but seem to be going wrong somewhere. The answer should be 366 kJ/mol, but I do not understand how to arrive at that solution. Thank you! a.) AHxn for the reaction below was determined using bond dissociation energies (BDEs) to be -57 kJ Using the table of BDE below, find the bond energy for H-Br c-C НН НН H-C-C-Br НН + H-Br Bond C-C с-с C-H C-Br H-Br Bond Enthalpy...
6 2 attempts left Check my work 6.66 points Enter your answer in the provided box. Sports trainers treat sprains and soreness with ethyl bromide. It is manufactured by reacting ethylene with hydrogen bromide: 11 + H- Print H References Use bond energies to find the enthalpy change for this reaction. kJ Average Bond Energies Bond Bond Enthalpy (kJ/mol) 432 C-c 347 614 cuc 839 CH 413 C-Br 276 Br-Br 193 H-Br 363
By using photons of specific wavelengths, chemists can dissociate gaseous HI to produce H atoms with accurately known speeds. When HI dissociates, the H atoms move away rapidly, whereas the relatively heavy I atoms move little. Use Table 9.2 in your textbook to answer the following questions: (a) What is the longest wavelength (in nm) that can dissociate a molecule of HI? 4.9) 406 nm (b) If a photon of 226 nm is used, what is the excess energy (in...
Part A Use the bond energies provided to estimate AH rx for the reaction below. 2 Bra(0) + C H2(g) - CH2Br4(0) AHpX = ? Bond Bond Energy (kJ/mol Br-Br 193 CEC 837 C-C 347 276 414 C-BI -228 kJ +407 kJ +573 kJ -648 kJ -324 kJ Submit Request Answer
Using the bond energies from the table below estimate ∆H for the following reaction C2H2(g) + H2(g) → C2H4(g) C-H (413), H-H (436), C-C (348), C=C (614), C≡C (839) A) +165 kJ/mol B) -390. kJ/mol C) +390. kJ/mol D) –124 kJ/mol E) –165 kJ/mol