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College officials want to estimate the percentage of students who carry a gun, knife, or other...

College officials want to estimate the percentage of students who carry a gun, knife, or other such weapon. A 9898% confidence interval is desired where the interval is no wider than 6 percentage points?

How many randomly selected students must be surveyed if we assume that there is no available information that could be used as an estimate of p^.

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Answer #1

Margin of Error, E = Z*

At 98% confidence level, Z* = 2.326

There is no estimate of . Therefore, consider = 0.5

Given value of E = 6% = 0.06

0.06 = 2.326 x

= 19.383

n = 376

376 students must be surveyed.

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