Please answer this question step by step. I'm very weak in Org chem. ___ 13. A...
Please answer this question step by step. I'm very weak in Org chem.
|
___ 13. |
A compound has the formula C8H9Br. Its 1H NMR spectrum consists of: doublet, d 2.0 quartet, d 5.15 multiplet, d 7.35 The IR spectrum shows two peaks in the 680-840 cm-1 region; one is between 690 and 710 cm-1 and the other is between 730 and 770 cm-1. Which is a possible structure for the compound? |
|||
|
A) |
p-BrC6H4CH2CH3 |
D) |
C6H5CHBrCH3 |
|
|
B) |
p-CH3C6H4CH2Br |
E) |
3,4-Dimethyl-1-bromobenzene |
|
|
C) |
C6H5CH2CH2Br |
|||
Homework Answers
The right answer is C6H5CHBrCH3 (Option D).
Explanation: The phenyl ring protons (5H, C6H5) gives a multiplet at 7.35 ppm.
The proton on the bromine-attached carbon (1H, CHBr) gives a quartet at 5.15 ppm
The methyl protons (3H, CH3) gives a doublet at 2.0 ppm.
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