Question

USING C++:

Write a function that will print out all the factors of a given positive integer N. The factors of N are all the numbers that N is divisible by (i.e., x is a factor of N if N/x has remainder 0). The function prototype is provided below.

E.g.  factors(12) will print out 1, 2, 3, 4, 6, 12.

void factors(int);

Answer 1

Code in c++ is:

#include<iostream>
using namespace std;
int main()
{
   int n;
   cout<<"Enter the number whose factors are to be printed: ";
   cin>>n;
   void factors(int);
   factors(n);
   return 0;
}
void factors(int n)
{
   cout<<"Factors are: ";
   for(int i=1;i<=n;i++)
   {
       if(n%i==0)
           cout<<i<<" ";
   }
   cout<<"\n";
}

Snapshot of code(for indentation reference):

Snapshot of output: