calculate the theroretical mean , standard dev, and variance simple size n=16 and process prob. = 0.10
Answer
Given :- sample size n = 16 and probability p = 0.10
Mean = n *p
= 16*0.10
= 1.6
And
Variance= n*p*q
where n = 100, p = 0.10 and q = 1-p = 1-0.10 = 0.90
this implies
variance = 16*0.10*0.90
= 1.44
and we know that standard deviation = sqrt{variance}
= sqrt{1.44}
= 1.2
So, mean = 1.6, variance = 1.44 and standard deviation = 1.2
calculate the theroretical mean , standard dev, and variance simple size n=16 and process prob. =...
a simple random sample of size n = 16 is drawn from a population that is normally distributed. The sample mean is found to be x = 50 and the standard deviation is found to be s = 11. Construct a 95% confidence interval about the populatio nmean
a ) ( mean, proportion, standard deviance or variance )
B ) is n > 30
C ) determine the parameter to be tested
D ) determine the test to be performed
B )
Determine the parameter to be tested, and the test to be performed. Part: 0 / 6 Part 1 of 6 A simple random sample of size 13 has mean x = 9.4. The population standard deviation is o = 3.72. The population is normally distributed. Can...
Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard deviation s=25 (population standard deviation is not known) Estimate confidence interval for population mean with confidence level 90%. Confidence Interval = Sample Mean ± Margin of Error Margin of Error = (t-value)×s/√n t-value should be taken from Appendix Table IV. For n=9 df=n-1=9-1=8 For Confidence Level 90% a = 1 - 0.90 = 0.10, a/2 = 0.10/2 = 0.05 So, we are looking for...
List all possible samples of size n=3, with replacement, from the population (1,3,5). Calculate the mean of each sample. Construct a probability distribution of the sample means and compute the mean, variance, and standard deviation of the sample means and compare to the mean, variance, and standard deviation of the population.
Calculate the mean, the variance, and the standard deviation of the following discrete probability distribution. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your final answers to 2 decimal places.)$$ \begin{array}{lrrrr} x & -23 & -17 & -9 & -3 \\ P(x=x) & 0.50 & 0.25 & 0.15 & 0.10 \end{array} $$Mean:Variance:Standard Deviation:
6. Calculate Variance ( s2) ______and standard error sM______from the following data n = 16 and SS = 960
A simple random sample of size 39 has mean 3.64. The population standard deviation is 1.55. Construct a 95% confidence interval for the population mean. 1.The parameter is the population (choose one) mean, proportion, standard deviation, variance 2. The correct method to find the confidence interval is (choose one) z, t, chi square method
Male Group (n=16, mean=11.00, SD=4.00) vs Female Group (16 females; mean=15.00, Variance = 9.00). Calculate the standard error of mean for the male and female group. Show your work with your answer. 44. Calculate standard error of distance between male and female group on the basketball free-throws. Show your work with your answer. -. Calculate the t-score for the basketball free-throws between male and female groups. -. Report the t test result in a statistical term, including the t-score and...
Calculate the mean, the variance, and the standard deviation of the following discrete probability distribution. (Negative values should be Indicated by a minus sign. Round Intermediate calculations to at least 4 decimal places. Round your final answers to 2 decimal places.) -7 Plx-x) О.33 0.33 0.24 0.10 -36 -22-10 Mean Standard deviation
A simple random sample of size n is drawn. The sample mean, x overbar, is found to be 17.7, and the sample standard deviation, s, is found to be 4.2. Construct a 95% confidence interval about mu if the sample size, n, is 35.