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The standard deviation of the lengths of hospital stay on the intervention ward is 7.4 days....

The standard deviation of the lengths of hospital stay on the intervention ward is 7.4 days. Complete parts​ (a) through​ (c) below. a. For the variable​ "length of hospital​ stay," determine the sampling distribution of the sample mean for samples of 91 patients. The standard deviation of the sample mean is sigma Subscript x overbarequals 0.7757 days. ​(Round to four decimal places as​ needed.) b. The distribution of the length of hospital stay is right skewed. Does this invalidate your result in part​ (a)? Explain your answer. A. ​No, because if x overbar is normally​ distributed, then x must be normally distributed. B. ​Yes, because the sample sizes are not sufficiently large that x overbar will be approximately normally​ distributed, regardless of the distribution of x. C. ​Yes, because x overbar is only normally distributed if x is normally distributed. D. ​No, because the sample sizes are sufficiently large that x overbar will be approximately normally​ distributed, regardless of the distribution of x.

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