Trucks in a delivery fleet travel a mean of 100 miles per day with a standard deviation of 29 miles per day. The mileage per day is distributed normally. Find the probability that a truck drives between 120 and 158 miles in a day. Round your answer to four decimal places.
Solution :
Given that ,
mean =
= 100
standard deviation =
= 29
P(120 < x <158 ) = P((120 - 100) /29 ) < (x -
) /
<
(158 - 100) / 29) )
= P(0.69 < z < 2)
= P(z < 2) - P(z < 0.69)
= 0.9772 - 0.7549
= 0.2223
Probability = 0.2223
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