Question

I am working on java patter. my code read the string and it will get only the numbers. in this case,124,140,130..but i want to get the maximum number. which is 140. I would appreciate any kind of help.

This is my code

public class questions {

   public static void main(String[] args) {
       int total=0;

       String test="it tookthismuch total time: 124. it tookthismuch total time: 140. it tookthismuch total time: 130. ";
      
       Pattern pat = Pattern.compile("(it tookthismuch total time:) (.+?) ");
       Matcher pro= pat.matcher(test);
       while (pro.find()) {
           total = Integer.parseInt(pro.group(2).replaceAll("\\D+", ""));      
           System.out.println(total);              
       }  
   }

}

The output

124
140
130

Answer 1

Hello, here is the completed code you wanted. Every important statement is explained using comments. Please check and let me know if you have any doubts. Thanks.

CODE

import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Questions
{
   public static void main(String[] args)
   {
       int i = 0;
      
       //creating an array to store values
       int array[] = new int[10];
      
       //initializing String test
       String test="it tookthismuch total time: 124. it tookthismuch total time: 140. it tookthismuch total time: 130. ";
      
       //creating a pattern instance
       Pattern pat = Pattern.compile("(it tookthismuch total time:) (.+?) ");
      
       //finding matches of the pattern in the test
       Matcher pro= pat.matcher(test);
      
       //loop to find occurrences of pattern in test
       while (pro.find())
       {
           //storing integer in array
           array[i] = Integer.parseInt(pro.group(2).replaceAll("\\D+", ""));
           i++;
       }
      
       //initializing max
       int max = array[0];
      
       //loop to find max
       for(i = 0; i < array.length; i++)
       {
           //if max is less than current element
           if(max < array[i])
               max = array[i];
       }
      
       //printing max
       System.out.println(max);
   }
}

OUTPUT

CODE SCREEN SHOT