a) 2 moles of octane gives 16 moles of CO2.
1 mole of octane will give 8 moles of CO2
1.5 moles of octane will give = 1.5 × 8 moles of CO2.
Moles of CO2 formed = 12 moles CO2
b.) Number of moles = Mass / molar mass
Molar mass of H2O = 18 g/mol
In this reaction 18 moles of water are formed.
Mass of water formed = 18 × 18
= 324 grams of water.
C.) 25 moles of oxygen reacts to give 18 moles of water.
1 mole of water will be formed by 25/18 moles of oxygen
Number of moles = Mass / molar mass
Moles of water = 90 / 18
Moles of water = 5 moles.
Moles of oxygen required =( 25/18) × 5
Moles of oxygen required = 6.94 moles
the complete combustion of octane , C8H18, a component og gasoline, proceed as 2 C8H18 +25...
The complete combustion of octane, C8H18, a component of gasoline, proceeds as is shown below. 2 C8H18(l) + 25 O2(g) 16 CO2(g) + 18 H2O(l) (a) How many moles of O2 are needed to burn 1.90 mol of C8H18? 23.75 mol (b) How many grams of O2 are needed to burn 2.50 g of C8H18? 8.75 g (c) Octane has a density of 0.692 g/mL at 20°C. How many grams of O2 are required to burn 1.85 gal. of C8H18?...
The complete combustion of octane, C8H18, a component of gasoline, proceeds as follows: 2C8H18(l)+25O2(g)→16CO2(g)+18H2O(g) a. How many moles of O2 are needed to burn 1.35 mol of C8H18? b. How many grams of O2 are needed to burn 13.0 g of C8H18? c. Octane has a density of 0.692 g/mL at 20 degrees C. How many grams of O2 are required to burn 1.20 gal of C8H18?
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How many moles of CO2 are emitted into the atmosphere when 26.6 g C8H18 is burned?
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How many moles of CO2 are emitted into the atmosphere when 25.6 g C8H18 is burned?
According to the following combustion reaction of gasoline (Octane), how many moles of C8H18 needs to be reacted to produce 16 moles of CO2? C8H18 (l) + 25/2 O2 (g) → 8CO2 (g) + 9 H2O
3) Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O How many moles of CO2 are emitted into the atmosphere when 22.6 g C8H18 is burned? CO2 emitted: 3A) Consider the following reaction. 2Fe2O3(s)+3C(s)−→−heat4Fe(s)+3CO2(g) Calculate the number of grams of Fe2O3 needed to react with 18.3 g C. mass of Fe2O3:
Here is the combustion reaction for octane (C8H18), which is a primary component of gasoline. How many moles of CO2 are emitted into the atmosphere when 17.1 g of C8H18 is burned?
The combustion of octane (C8H18) in oxygen proceeds as follows 2 C8H18(g) + 25 O2(g) ---> 16 CO2 (g) + 18 H2O(l) How many moles of CO2are produced when 5.0 moles of octane, C8H18, is burned in 5.0 moles of oxygen?
The complete combustion of octane, C8H18, a component of gasoline, proceeds as follows: 2C8H18(l)+25O2(g)→16CO2(g)+18H2O(g) Relevant volumetric equivalencies 1 gal = 3.785 L 1 L = 1000 mL part C Octane has a density of 0.692 g/mL at 20∘C. How many grams of O2 are required to burn 17.0 gal of C8H18? Express the mass in grams to three significant digits.
Octane, a component of gasoline, can undergo the following combustion with an excess of oxygen gas: 2 C8H18 (ℓ) + 25 O2 (g) → 16 CO2 (g) + 18 H2O (ℓ) 10.0 mL of octane and 1.50 atm of oxygen gas are placed in a 20.0 L container at 20.0°C. Calculate the total pressure in the container after complete combustion (in atm). (Assume the vapor pressures of water and octane are negligible and temperature and volume remain constant. The density...