Question

How much heat is required to raise the temperature of 60 grams of water from 25-degrees Celsius to 85 degrees Celcius?

Answer 1

specific heat of water is 4.187 kJ/kgK.

∆t = 85℃-25℃ = 60℃

m = 60g = 0.060 kg

This means 4.187 kJ will raise the temperature of 1 Kg water 1 degree K (= 1 degree C)

you need to raise 0.06 Kg water 60 degrees.

i.e (85℃-25℃ = 60℃)

∆E = mc∆t

=60℃ x 0.060 Kg x 4.187 kJ / Kg degree = 15.1 kJ......Answer.

Hope this helps.