Question

C programming Question (Please help if you can)

- Create a "loop" that will execute n times, displaying numbers starting at b and incrementing by i. The numbers that would result should be inserted into an array

for example

n = 5

b = 6

i = 4

resulting array= {6 10 14 18 22}

--------------------------------

n = 6

b = 10

i = 3

resulting array = {10 13 16 19 22 25}

Answer 1

ANSWER: Here I am giving you the code and output before downvote kindly comment on your problem or like it, please.

CODE:

#include <stdio.h>

int main()
{
int n,b,i,j;
printf("n= ");
scanf("%d",&n);
printf("b= ");
scanf("%d",&b);
printf("i= ");
scanf("%d",&i);
int arr[n],m=n,k;
for(j=0;j<n;j++){
  
if(j==0)
arr[j]=b;// for first element it should be b
else{
arr[j]=arr[j-1]+i; // and next values will be previous + value of i
}
}
printf("resulting array = ");
for(k=0;k<m;k++){
printf("%d ",arr[k]);
}
return 0;
}

OUTPUT: