Question

first = 4
second = −5
if first > 0 and second >= 0:
   result = second//first
elseif first == second or first < second:
   result = first∗second
else :
   result = second∗2
  
   print ( result )

since while first>0 succeeds, second >=0 fails, and both first==second and first

translate the above code to a properly commented MIPS program

Answer 1

Please upvote ,comment if any query . Thanks .

Note : check attached image for output and code . Code compiled and tested in MARS Simulator MIPS.

Program :

.data
   result: .asciiz "result is: "
.text
   addi $s0,$zero ,4 #first =4
   addi $s1,$zero ,-5 #second =-5
   addi $s2,$zero ,0 #result=0
  
  
   sgt $t0,$s0,0 #if first>0 set $t0=1
   sge $t1,$s1,0 #if second>=0 set $t1=1

   
    beq $t0,0,elseif #if t0 equal to 0 go to elseif
   beq $t1,0,elseif #if t1 equal to 0 go to elseif
   #if above both not true calculate result
  
   div $s2,$s0,$s1 #result = first//second // operator return integer value of divide
   j Result #go to result label
  
  
elseif: #else if


seq $t2,$s0,$s1 #first==second $t2=1
    slt $t3,$s0,$s1 #first<second $t3=1

    beq $t2,1,calculateResult #if t2 equal to 1 go to calculateResult
    beq $t3,0,else #if t3 equal to 0 go to else
    #elseif condition both are zero
calculateResult:
#result = first*second
    mul $s2,$s0,$s1
    jal Result  
      
else : #else
   #result = second*2

   mulo $s2,$s1,2
  
  
   j Result
   
Result: #pprint result
  
   #print result is string
   li $v0,4
   la $a0,result
   syscall
  
#print result variable
   li $v0,1 #print result
   addi $a0,$s2,0
   syscall
     
   #terminate the program
li $v0,10 #exit
   syscall
   
  
   
   
   
   
   

   
Output : when first=4 result =5 will go to if

   Output : when first=-4 result =-4 will go to else if

   Output : when first= 4 result =-5 will go to else