Question

**IN C++ ONLY** Calculate the area and volume of a sphere problem. Inside a for loop, vary the radius from 10 to 40 with a step or increment of 5 and calculate the area and volume Your radius will be equal to your loop counter. All calculations should have 2 decimal places, but the radius should have zero decimal places and any number of 1,000 or more should have a comma. Print the radius, area, and volume in a table format, with 3 columns. Note: you don’t have to print grid lines. Print column headings above the loop and all the calculations inside the loop. The column headings would just be Radius, Area, and Volume. Right justify your data under your column headings Below the loop, print the sum of the radii, the sum of the areas, and the sum of the volumes. The sum of the areas and the sum of the volumes should have 2 decimal places and commas. The sum of the radii should have zero decimal places. **IN C++ ONLY**

Answer 1

#include <iostream>
#include <string>
using namespace std;

string commify(unsigned long long n)
{
string s;
int cnt = 0;
do
{
s.insert(0, 1, char('0' + n % 10));
n /= 10;
if (++cnt == 3 && n)
{
s.insert(0, 1, ',');
cnt = 0;
}
} while (n);
return s;
}

float Round(float var)
{
float value = (int)(var * 100 + .5);
return (float)value / 100;
}

int main()
{
float sum_radius=0;
float sum_area=0;
float sum_volume=0;
float area,volume;


std::cout << "radius "<<"Area " << "volume"<< std::endl;
for(int radius=10;radius<=40;radius+=5)
{
std::cout <<radius;
sum_radius +=radius;

area=4 * 3.14 * radius * radius;

std::cout <<" "<<commify(Round(area));
sum_area +=area;

volume=(4/3)*3.14 * radius * radius * radius;

std::cout <<" "<<commify(Round(volume))<< std::endl;
sum_volume +=volume;

}

std::cout << "Sum of radius :"<<commify(Round(sum_radius))<< std::endl;
std::cout << "Sum of area :"<<commify(Round(sum_area))<< std::endl;
std::cout << "Sum of volume :"<<commify(Round(sum_volume))<< std::endl;
}

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