Question

A wire has a length of 4.53 × 10-2 m and is used to make a circular coil of one turn. There is a current of 5.17 A in the wire. In the presence of a 6.92-T magnetic field, what is the maximum torque that this coil can experience?

Answer 1

The torque on a current carrying loop in an external magnetic field is given by the formula

Where the parameters are

N = no of turns

A = area of the loop

B = external magnetic field

I = current in the loop

Theta = angle between area vector and magnetic field.

Here, the total wire length is 4.53cm,

That is the circumference,

From this we get the diameter,

And hence the area,

Now the torque formula

Angle is taken as 90 for max value of sin(theta).

Finally