A 640 kg sample of water at 0°C is cooled to -6°C, and freezes in the process. How much heat is liberated? (For water L_{f} = 334 kJ/kg and L_{v} 2257 kJ/kg. The specific heat for ice is 2050 J/kg∙K.)
Group of answer choices
A)14,100 kJ
B)176,000 kJ
C)222,000 kJ
D)320,000 kJ
total heat = m * lf + m c delta_T
= 640 * 334 + 640 * 2.05 * 6
= 213760 + 7872
= 221632 kJ
= approx 222000 kJ ...
so answer is option C
A 640 kg sample of water at 0°C is cooled to -6°C, and freezes in the...
A 3873 kg sample of water at 0 C is cooled to-13 C and freezes in the process. How much heat is liberated? (for water Lf= 334 kj/kg and Lv= 2257 Kj/kg. The specific heat for ice is 2050 J/kg*K)
(TCO 7) Heat is added to a 5.0 kg piece of ice at a rate of 454.0 kW. How long will it take for the ice at 0.0 °C to melt? (For water, Lf = 334 kJ/kg and Lv = 2257 kJ/kg.)
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How much heat is required to convert solid ice with a mass of 585 g and at a temperature of -29.0 °C to liquid water at a temperature of 74.5 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
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