Question

python3.x

Write a function print_letter_count(word) that takes a string as a parameter and prints each unique character (in alphabetical order and lowercase) together with their frequency. For example: consider the following word:

Programming

The characters are: 1 x p, 2 x r, 1 x o, 2 x g, 1 x a, 2 x m, 1 x i and 1 x n. The output would be:

a: 1
g: 2
i: 1
m: 2
n: 1
o: 1
p: 1
r: 2

Note:

• The parameter string may contain uppercase letters
• The output is in alphabetical order.

For example:

Test	Result
print_letter_count('Programming')	a: 1 g: 2 i: 1 m: 2 n: 1 o: 1 p: 1 r: 2
print_letter_count('Combination')	a: 1 b: 1 c: 1 i: 2 m: 1 n: 2 o: 2 t: 1

Answer 1

Hey here is answer to your question.

In case of any doubt comment below. if you liked the answer feel free to upvote this.

Explanation :- how it works is we take a string and we make a dict in python. then we loop over the string and check if its exist in dict then increase the counter.

def print_letter_count(string):
   string =string.lower()
   answer = {}
  
   for i in string:
   if i in answer:
   answer[i] += 1
   else:
   answer[i] = 1
   for i in sorted(answer.keys()):
      print(str(i) + " : "+str(answer[i]))

#print_letter_count('Programming')
print_letter_count('Combination')