Question

Write a program that first reads an integer for the array size, then reads numbers into the array, computes their average, and finds out how many numbers are above the average.

Make sure to include pointer syntax.

Example output:

Enter array size: 10

10 random numbers between 1 and 10 generated are: 2 8 5 1 10 5 9 9 3 5

The average is: 5.7

Number of items above the average = 4

C++ Code only.

Answer 1

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>

using namespace std;

int main() {
    srand(time(NULL));
    int n;
    cout << "Enter array size: ";
    cin >> n;
    int *arr = new int[n];
    double avg = 0;
    cout << n << " random numbers between 1 and " << n << " generated are:";
    for (int i = 0; i < n; ++i) {
        *(arr+i) = (rand() % n) + 1;
        avg += *(arr+i);
        cout << " " << *(arr+i);
    }
    cout << endl;
    avg /= n;
    cout << "The average is: " << avg << endl;
    int count = 0;
    for (int i = 0; i < n; ++i) {
        if (*(arr + i) > avg)
            ++count;
    }
    cout << "Number of items above the average = " << count << endl;
    delete[] arr;
    return 0;
}