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A ball is thrown from a point 1.0 m above the ground. The initial velocity is...

A ball is thrown from a point 1.0 m above the ground. The initial velocity is 20.5 m/s at an angle of 25.0° above the horizontal. (a) Find the maximum height of the ball above the ground. m (b) Calculate the speed of the ball at the highest point in the trajectory. m/s

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Answer #1

a)

motion along vertical

h = ho + ( u sin x)^ 2/ 2g

h = 1 + ( 20.5 sin 25 ^2 / 19.6

h = 4.829 m

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b)

at highest point only horizontal component of velocity acts

v = vx = 20.5 cos 25 = 18.58 m/s

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Comment in case any doubt, will reply for sure. Goodluck

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