Question

I need to return a dynamic array from a class member function and print out the results in main. using pointers and dynamic allocation is required.

class example{

int *test

public:

example(int a){

test = new int[a];

for(int i=0;i<a;i++)

test[i]=i;

}

int *send(){ return test;}

}

int main(){

example a(3);

int *practice = a.send();

int psize = sizeof(a)/sizeof(a[0]);

for(int i=0;i<psize;i++)

cout <<practice[i] << endl;

return 0;

}

Answer 1

Here I implemented dynamic memory allocation function. In my program, I add new function len for returning the size of an array. So now there no need for psize in main.

#include<bits/stdc++.h>
using namespace std;
class example
{
int *test,l; //l is for length of an array
public:
example(int a)
{
l=a;
test = new int[a]; //dynamic memory allocation
for(int i=0;i<a;i++)
test[i]=i;
}
int* send() //return first pointer of an array
{
return test;
}
int len() //return length of an array
{
return l;
}
};
int main()
{
example a(3); //object of example class
int *practice = a.send();
for(int i=0;i<a.len();i++)
{
cout <<*practice<< endl;
practice++; //increment pointer
}
return 0;
}

Output:

0

1

2