Question

def blur(img: Image) -> Image:
    """Blur Image, img, based on the given pixel_size

    Hints:
    - For each pixel, calculate average RGB values of its neighbouring pixels
        (i.e. newRed = average of all the R values of each adjacent pixel, ...)
    - Set the RGB value of the center pixel to be the average RGB values of all
        the pixels around it
    
    Be careful at the edges of the image: not all pixels have 8 neighboring pixels!
    """

please use python

only the following methods are allowed to use

- Image.new(mode, size, color): creates a new image (use 'RGB' for mode)

- Image.open(filename): opens an existing image file

- Image.size: returns the image size in pixels as a 2-tuple, (width, height)

- Image.load(): returns a PixelAccess object of all of the image's pixels

- Image.show(): display the image represented by the Image object

- Image.save(filename): saves an image

- Image.close(): closes an open Image file

provide notes beside each line of code would be appreciate thanks!

Answer 1

CODE TO COPY:

# Imports PIL module
from PIL import Image

#average function to take a list and find average values of RGB and return that RGB tuple
def avg(x):
a=b=c=0
for i in x:
a=a+i[0]
b=b+i[1]
c=c+i[2]
s=len(x)
return (int(a/s),int(b/s),int(c/s))

def blur(im):
#load() function gives us the pixel object which is used to access any pixel
am = im.load()
  
#getting our image size and width so that to create new image of same size
width=im.size[0]
height=im.size[1]
  
#creating new image of same size
  
ima=Image.new(mode="RGB",size=(width,height))
#getting pixel object of new image
ama=ima.load()
  
#iterating throughout the image ans storing its average of around 8 pixels
for i in range(width-1):
for j in range(height-1):
ama[i,j]=avg([am[i-1,j-1],am[i-1,j],am[i-1,j+1],am[i,j-1],am[i,j+1],am[i+1,j-1],am[i+1,j],am[i+1,j+1]])

#showing image
ima.show()
  
#saving image
ima.save("new.png")
  
# open method used to open different extension image file
im = Image.open("code.png")
blur(im)