1. A student ran the following reaction in the laboratory at
632 K:
2HI(g)
->H2(g) +
I2(g)
When she introduced 0.362 moles of
HI(g) into a 1.00 liter container, she found the
equilibrium concentration of I2(g) to
be 3.55×10-2 M.
Calculate the equilibrium constant, Kc, she obtained for
this reaction.
Kc =
2. A student ran the following reaction in the laboratory at
616 K:
CO(g) + Cl2(g) ->
COCl2(g)
When she introduced 0.131 moles of
CO(g) and 0.161 moles of
Cl2(g) into a 1.00 liter container, she
found the equilibrium concentration of
Cl2(g) to be
6.37×10-2 M.
Calculate the equilibrium constant, Kc, she obtained for
this reaction.
Kc =
1. A student ran the following reaction in the laboratory at 632 K: 2HI(g) ->H2(g) +...
A student ran the following reaction in the laboratory at 673 K: H2(g) + I2(g) 2HI(g) When she introduced 0.228 moles of H2(g) and 0.256 moles of I2(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 6.53×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
A student ran the following reaction in the laboratory at 647 K: 2HI(g) H2(g) + I2(g) When she introduced 0.395 moles of HI(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 3.95×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
A student ran the following reaction in the laboratory at 686 K: H2(g) + I2(g) 2HI(g) When she introduced 0.200 moles of H2(g) and 0.230 moles of I2(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 6.18×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc=?
A student ran the following reaction in the laboratory at 529 K: CoCl2(g) P CO(g) + Cl2(g) When she introduced 1.68 moles of CoCl2(g) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 3.61*10-2 M. Calculate the equilibrium constant, Ke she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 425 K: PCl5(g) --> PCl3(g) + Cl2(g) When she introduced 4.59 moles of PCl5(g) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 3.94×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
1) A student ran the following reaction in the laboratory at 306 K: CH4(g) + CCl4(g) 2CH2Cl2(g) When she introduced 3.94×10-2 moles of CH4(g) and 5.52×10-2 moles of CCl4(g) into a 1.00 liter container, she found the equilibrium concentration of CH2Cl2(g) to be 8.23×10-3 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc= 2) A student ran the following reaction in the laboratory at 333 K: CH4(g) + CCl4(g) 2CH2Cl2(g) When she introduced 3.94×10-2 moles of CH4(g)...
A student ran the following reaction in the laboratory at 557 K: CO(g) + Cl2(g) = COCl2(g) When she introduced 1.06 moles of CO(g) and 1.09 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of COCl2(g) to be 1.02 M. Calculate the equilibrium constant. Ko she obtained for this reaction. Ke=
A student ran the following reaction in the laboratory at 541 K: COC12(E) CO(g) + Cl2(g) When she introduced 1.13 moles of COC12(e) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 3.83x10-2 M. Calculate the equilibrium constant, K, she obtained for this reaction.
A student ran the following reaction in the laboratory at 254 K: 2NO(g) + Br2(g) ⇌ 2NOBr(g) When she introduced 0.185 moles of NO(g) and 0.130 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.152 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 225 K: 2NOBr(g) 2 2NO(g) + Brz(g) When she introduced 0.198 moles of NOBr(g) into a 1.00 liter container, she found the equilibrium concentration of Br2(g) to be 1.89x10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =