What is the concentration of Fe3+ in a solution of 1.5 mL of 0.020 M KI,...
Calculate the molarity of Fe3+ in solution A. Solution A: 10 mL of 0.0600 M Fe(No3)3 + 15 mL DI water.
What is the final concentration of Fe 3+ in a solution if you add 2.5 mL of 3.0M Fe(NO3)3 and 3.2 mL of water in a test tube?
If you add together 10.0 ml of 0.020 M FeCl3 and 20.0 ml of 0.020 M KI in a beaker what is the initial molar concentration of the KI before the reaction occurs?
Soln. 2.5x10-3 M Fe(NO3)3 mL 2.5X10-3 M KSCN mL 0.5 M HNO3 mL Absorbance A 5 1 4 0.020 B 5 2 3 0.034 C 5 3 2 0.037 D 5 4 1 0.056 E 5 5 0 0.066 Calibrated at max wavelength of FeSCN2+ = 485.80nm Final concentration of Fe3+ = 5.56*10-5 Using M1V1=M2V2, calculate the initial concentrations of the reactant Fe3+, (m) and SCN- (n) in each solution A-E.
A student mixes 5.12 mL of 4.02 x 10 M Fe(NO3)3 with 4.88 mL 2.01 x 103 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN2 is 1.40 x 10 M. 1. What is the initial concentration in solution of the Fe3 and SCN'? What is the equilibrium constant for the reaction? What happened to the K' and the NO3 ions in this solution? a. b. C.
A student mixes 5.12 mL of 4.02 x 10...
For the reaction Fe3+ + SCN 1- FeSCN2+ 9.00 mL of 0.00800M Fe(NO3)3 were diluted to a volume of 450.0 ml, then... 4.00 mL of the diluted Fe(NO3)3 were mixed with 4.00 mL of KSCN and 4.00 mL of HNO3. Calculate the initial concentration of Fe3+ at the time of mixing. Short answer LE- _ (no extra Scientific notation format spaces) How many mL of 0.00200 M Fe(NO3)3 are required to prepared 12.50 mL total volume with a concentration of...
A mixture is prepared by combining 3.0 mL of 0.0050 M NaSCN solution with 4.0 mL of 0.0030 M Fe(NO3)3 solution, and 3.0 mL of 0.10 M HNO3 1.if Keq = 428.8, determine the equilibrium concentration of FeSCN2+ in the solution. (keep 4 decimal places) 2.if Keq=280, determine the equilibrium concentration of Fe3+ in the solution. (keep 4 decimal places) 3.if Keq = 343, determine the equilibrium concentration of SCN-- in the solution. (keep 4 decimal places)
A student took 5.03 mL 0.200 M Fe(NO3)3 solution, added 25.18 mL of DI water, mixed the resulting solution thoroughly and placed the solution in a 50 mL buret. Then, the student took 10.09 mL of this dilute solution from the buret and mixed it thoroughly with 6.21 mL 0.00200 M NH4SCN and 28.65 mL DI water to form the reaction system. What are the initial [Fe3+] and the initial [SCN-] in this reaction system? ( ) [Fe3+]Initial = 7.47...
4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of distilled water were mixed. The resulting solution was allowed to attain equilibrium at 24 oC. The absorbance of the equilibrium solution was recorded, and the [FeSCN2+] was determined graphically to be 7.58 x 10-5 M. Part A: Calculate the number of moles of Fe3+ initially added to the solution. Part B: Calculate the number of moles of FeSCN2+ formed in the solution at equilibrium....
Table A. Preparation of Standard solutions of FeSCN2+ 1.0 M HNO3 0.002 M 0.200 M Solution KSCN (mL) Fe(NO3)3 (mL) 0.5 5 [FeSCN2+] (mol/L)* 1 4.0x10^-5 Add 1.0 M 2 1.0 5 8.0x10^-5 HNO3 3 1.5 5 1.2x10^-10 4 2.0 5 1.6x10-4 to each to adjust the volume to 25 mL. 5 2.5 5 2.0x10-4 * Calculate the concentrations of FeSCN2+ in each beaker, assuming that all SCN-ions exist as FeSCN2+. In other words, [FeSCN2+] (in Soln 1) = [SCN-]...