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A beam of light consisting of two wavelengths, 546.0 nm and 409.5 nm, is used to...

A beam of light consisting of two wavelengths, 546.0 nm and 409.5 nm, is used to illuminate two slits. The separation between the slits is 0.400 mm and the resulting interference patterns are observed on a screen that is 1.00 m from the slits. Calculate the minimum distance from the central maximum at which bright fringes from both patterns coincide

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Answer #1

Given:

D= 1m

d= 0.4mm = 4 × 10-4 m

Let the distance of bright fringes from both patterns is given as:

So,

Therefore,

Because, n1 and n2 can't be zero so,

n1 =3 and n2 = 4

Therefore,

y= 0.4095 cm

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