The results of a one-sample t test were t (18) = 2.11, p < 0.05. In this example, the sample size is (report as a whole number):
Given that, for one-tailed test, t(18) = 2.11
and p-value is less than 0.05 ( i.e. p < 0.05)
Here, degrees of freedom = n - 1 = 18
So, n = 18 + 1 = 19
Therefore, required sample size is 19
The results of a one-sample t test were t (18) = 2.11, p < 0.05. In...
The results of an independent-samples t test were t(19) = 4.02, p =0.01. In this example, the sample size is ___.
The results of a single-sample t test are reported as t(44) = −3.35, p < .001, d = −0.50. Describe the effect size for this study.
Use the t-distribution and the sample results to complete the test of the hypotheses. Use a 5% significance level. Assume the results come from a random sample, and if the sample size is small, assume the underlying distribution is relatively normal. Test H0 : μ=10 vs Ha : μ>10 using the sample results x¯=13.2, s=8.7, with n=12. test statistic = p-value =
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A researcher conducted a single sample t-test on results of an experiment with n = 18 participants and the computed t = -2.28. What is the correct conclusion from this experiment if p < 0.05, 2-tails test is used for hypothesis testing? O A. The researcher failed to reject the null hypothesis and concluded that there is a significant treatment effect. O B. The researcher rejected the null hypothesis and concluded that there is a significant treatment...
You wish to test the following claim at a significance level of α=0.05 H0:p=0.65 H1:p≠0.65 You obtain a sample of size n=684 in which there are 436 successful observations. What is the test statistic for this sample? (Report answer accurate to 3 decimal places.)
QUESTION 20 How would we report the following results of a t-test? One-Sample Test Test Value = 7 95% Confidence interval of the Mean Difference Sig (2-tailed) Difference Lower Upper Digitspan 2 364 68 021 542029 8 457 9.9949 t(68) = 2.364, p = .021 t(67) = 2.364, p = .021 t(68) = 5.42, p = .021 t(68) = .021, p = 2.364 QUESTION 21 Fill in the missing numbers in the ANOVA table below: ANOVA Source of Variation S...
A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ , of the population from which the sample was drawn. Use the P-value approach. Also, assess the strength of the evidence against the null hypothesis. sample mean = 24.4, s = 9.2, n=25, H0: μ = 26, Ha : μ , 26, α = 0.05 Options: A: Test statistic: t = -0.87. P-value = 0.1922....
Use the t-distribution and the sample results to complete the test of the hypotheses. Use a 5% significance level. Assume the results come from a random sample, and if the sample size is small, assume the underlying distribution is relatively normal. Test H0 : μ=4 vs Ha : μ≠4 using the sample results x¯=4.8, s=2.3, with n=15. ME: 99% confidence interval
For a test of Ho: p = 0.50 and Ha: p < 0.50, the sample proportion is 0.42 based on a sample size of 100. Report the value of the test statistic. Round your final answer to three decimal places and enter only a number. (That is, do not include any letter or the = sign)
Consider the following hypothesis test: H0: μ = 18 Ha: μ ≠ 18 A sample of 48 provided a sample mean x = 17 and a sample standard deviation s = 4.9. a. Compute the value of the test statistic (to three decimal places.) b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value. (to two decimal places) p-value is between is c. At α = .05, what is your conclusion? p-value...