A buffer is made having a weak acid concentration of 0.50 M and a conjugate base concentration of 0.67 M. If the weak acid has a Ka of 4.5 x 10-6, what is the pH of the buffer? Answer with 3 sig figs.
Answer
pH = 5.48
Explanation
pKa = -logKa
pKa of the weak acid = -log(4.5×10-6) = 5.35
Henderson - equation is
pH = pKa + log([A-]/[HA])
pH = 5.35 + log(0.67M/0.50M)
pH = 5.35 + 0.13
pH = 5.48
A buffer is made having a weak acid concentration of 0.50 M and a conjugate base...
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Ka
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