Question about ACID/BASE. Equal volumes of 0.230 M weak base (Kb = 4.0× 10–9) and 0.230...
Question about ACID/BASE. Equal volumes of 0.230 M weak base (Kb = 4.0× 10–9) and 0.230 M HCl are mixed. Calculate the pH of the resulting solution. Please show all your work.
Homework Answers
Assume weak base is BOH
BOH + HCl ----> BCl + H2O
If volume is equal then concentration becomes half. C= 0.115 M
It undergoes salt hydrolysis
It is salt of weak base+strong acid
pKb = -log(Kb) = 8.40
Now pH
pH = 1/2(14-pKb - log[C])
= 1/2(14-8.4-log(0.115))
= 3.3
pH = 3.3
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