You have a 10-lb bag of dry alum, Al2(SO4)3(a) Calculate the number of gallons of 0.05 M solution you can make with this amount of alum. (b) Suppose you put all the alum into a 42-gal barrel and filled it full.Calculate the molar concentration of the resulting solution.
You have a 10-lb bag of dry alum, Al2(SO4)3(a) Calculate the number of gallons of 0.05...
2. You have an empty 42-gal barrel and a 5-lb bag of dry alum, Al2(SO4)s and are interested in making a 0.05 M solution with these materials. (a) Calculate the number of gallons of 0.05 M solution you can make with the materials you have on hand. (b) Suppose you put all the alum in the barrel and filled it full. Calculate the molar concentration of the resulting solution.
2. You have an empty 42-gal barrel and a 5-lb bag...
2. You have an empty 42-gal barrel and a 5-lb bag of dry alum, Al:(SO4)s and are interested in making a 0.05 M solution with these materials. (a) Calculate the number of gallons of 0.05 M solution you can make with the materials you have on hand. (b) Suppose you put all the alum in the barrel and filled t full. Calculate the molar concentration of the resulting solution.
a) How many mol of Al2(SO4)3 are required to make 40 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? c) What mass of Al2(SO4)3 is required to make 40 mL of a 0.050 M...
a) How many moles of Al2(SO4)3 are required to make 44 mL of a 0.090 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 44 mL of...
a) How many moles of Al2(SO4)3 are required to make 55 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 55 mL of...
a) How many moles of Al2(SO4)3 are required to make 43 mL of a 0.060 M Al2(So4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(S04)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 43 mL of...
Question 1 : a) Show the calculation of the mass of Al2(SO4)3 needed to make 200ml of a 0.250 M solition. report your answer to 3 significant figures. b) show the calculation of the volume of 0.667 M solution which can be prepared using 37.5 grams of Ba(NO3)2 c)show the calcultion of the freezing point of a solution made by dissolving 15.6 grams of the nonelectrolyte C3H6O3 in 200 geams of water. Kf for water is 1.86, freezing point of...
ANAL 425: Titrating Hydrochloric Acid Solution with a
Standard Sodium Hydroxide Solution
ANAL 42: The Hydrochlork Acil Solution with Standard Sodium Hydroxide Solution (3) Calculate the number of equivalents of acid in 1.00 lb of dry acid powder. The molar mass of NaHSO, is 120.07 g mol (4) Calculate the mass, in pounds, of dry acid powder required to supply the equivalent amount of acid present in 1 qt (0.9463 L) of the commercial muri- atic acid solution discussed in...
Electrolytes, Concentration and Dilution of Solutions n this part of the experiment, you will make a dilution of a stock solution of known concentration and calculate the concentration of the dilute solution. DILUTION OF A STOCK SOLUTION PART C: Measurements and Observations Procedure Check out a 100-mL volumetric flask from your instructor. Fill test tube about 2/3 concentration of the active ingredient from its label including units. Record 1. orlt O " concentration of active ingredient. full of "Magic 2....
3. Concentrations in solids and solution. You send a 10-g sample of rice to the lab for the determination of the total arsenic content. The analyst dissolves 1.0 g of the rice in 5.0 mL of concentrated acid and then dilutes the solution to a final volume of 25.0 mL. When analyzed by ICP-MS, the solution concentration is found to be 35 µg L-1. What is the concentration of arsenic in the rice (in µg kg-1)? ___________ ppb Hint: Follow...