Two tickets are drawn from a box with 5 tickets numbered as follows: 1,1,3,3,5.
If the tickets are drawn with replacement, find the probability that the first ticket is a 1 and the second ticket is a 5.
If the tickets are drawn without replacement, find the probability that the first ticket is a 1 and the second ticket is a 3.
If the tickets are drawn without replacement, find the probability that the first ticket is a 1 and the second ticket is a 1.
Can someone explain this? I don't get it. I also don't understand what its mean by with replacement or without replacement.
a) P(first ticket is 1 and second is 5) = P(first is 1) * P(second is 5) = 2/5 * 1/5 = 0.08
b) P(first ticket is 1 and second is 3) = P(first is 1) * P(second is 3) = 2/5 * 2/4 = 0.2
c) P(first ticket is 1 and second is 1) = P(first is 1) * P(second is 1) = 1/5 * 1/4 = 0.05
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