A 150 kg mass and a 90 kg mass are suspended from a 100 kg board...
A 150 kg mass and a 90 kg mass are suspended from a 100 kg board of length 6 m. So that the board is horizontal, the cable should be attached ___m from the left end of the board. Also, the tension on the cable will be ___N rounded to the nearest integer.
Homework Answers
let the cable is at a distance x from the left end
balancing the torque about the pivot
150 * x * 9.8 - 100 * 9.8 * (6/2- x) - 90 * 9.8 * (6 - x) = 0
solving for x
x = 2.47 m
the distance from the left end is 2.47 m
for the tension in the cable
tension in the cable = total weight
tension in the cable = (150 + 90 + 100) * 9.8
tension in the cable = 3332 N
the tension in the cable is 3332 N
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