A diver comes off a board with arms straight up and legs straight down, giving her...
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis of 22 kg⋅m^2. She then tucks into a small ball, decreasing this moment of inertia to 4.2 kg⋅m^2. While tucked, she makes two complete revolutions in 2.1 s. If she did not tuck, how many revolutions would she have made in the same time?
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A diver comes off a board with arms straight up and legs
straight down, giving her...
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotati...
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis of 18kg?m2. She then tucks into a small ball, decreasing this moment of inertia to 3.6kg?m2. While tucked, she makes two complete revolutions in 1.0s . If she hadn't tucked at all, how many revolutions would she have made in the 1.8s from board to water?
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotati...
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis of . She then tucks into a small ball, decreasing this moment of inertia to . While tucked, she makes two complete revolutions in 1.3 . If she hadn't tucked at all, how many revolutions would she have made in the 1.7 from board to water? Express your answer using two significant figures. =_____________rev
When a diver gets into a tuck position by pulling in her arms and legs, she...
When a diver gets into a tuck position by pulling in her arms and legs, she increases her angular speed. Before she goes into the tuck position, her angular velocity is 5.5 rad/s, and she has a moment of inertia of 1.8 kg · m2. Once she gets into the tuck position, her angular speed is 17.1 rad/s. Determine her moment of inertia, in kg · m2, when she is in the tuck position. Assume the net torque on her...
Name Lecture Section: 8amロ11am 3pm physID PHYS 141 -Written Homework #11 (Chapter 10b) Due Date:...
Name Lecture Section: 8amロ11am 3pm physID PHYS 141 -Written Homework #11 (Chapter 10b) Due Date: 11:59pm on Friday, April 12, 2019 For full credit, clear, legible, and correctly-rotated pages must be submitted to the correct location 1. (4 points) (Text 10.52) A gyroscope on the Moon. A certain gyroscope precesses at a rate of 0.500 rds when used on Earth. If it were taken to a lunar base, where the acceleration due to gravity is 0.165g, what would be its...
A diver with a mass of 62.0 kg is rotating head-over-heels in mid-air, at an angular...
A diver with a mass of 62.0 kg is rotating head-over-heels in mid-air, at an angular speed of 3.00 revolutions per second, in a tucked position (that is, with arms, legs, and head pulled into a tight ball). In this position, the diver can be modeled as a solid sphere with a radius of 0.600 m, rotating about its center. Just before landing, while still in the air, the diver fully extends her arms and legs. In this position, she...
A competitive diver leaves the diving board and falls toward the water with her body straight and rotating slowly. She...
A competitive diver leaves the diving board and falls toward the water with her body straight and rotating slowly. She pulls her arms and legs into a tight tuck position. What happens to her angular speed? -increase -decrease -stay the same -impossible to determine What happens to the rotational kinetic energy of her body? -increase -decrease -stay the same -impossible to determine
A diver leaves the platform with her body straight. Her body is in a relatively slow...
A diver leaves the platform with her body straight. Her body is in a relatively slow rotation, with an angular speed of 4.0 rad/s. She then tucks into a pike position, with her body essentially folded in half. When straight her moment of inertia is 13.5 kg·m2, and when in the pike position it is 3.4 kg·m2. The next two questions have to do with this diver. Calculate her angular momentum when straight. a. 6 kg·m2/s b. 39 kg·m2/s c....
A ballerina spins on her toe, essentially without friction. She starts the spin with her arms...
A ballerina spins on her toe, essentially without friction. She starts the spin with her arms extended outward from her body. When she brings her arms up, closer to her axis of rotation, which of the following occurs. A: She increases her moment of inertia, thereby increasing her angular speed B: She increases her moment of inertia, thereby decreasing her angular speed C: She decreases her moment of inertia, thereby increasing her angular speed D: She decreases her moment of...
A diver (such as the one shown in the figure(Figure 1) ) can reduce her moment of inertia by a factor of about 3.5 when...
A diver (such as the one shown in the figure(Figure 1) ) can reduce her moment of inertia by a factor of about 3.5 when changing from the straight position to the tuck position. A) If she makes 2.0 rotations in 1.5 s when in the tuck position, what is her angular speed (rev/s) when in the straight position?
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and...
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
Name Lecture Section: 8amロ11am 3pm physID PHYS 141 -Written Homework #11 (Chapter 10b) Due Date: 11:59pm on Friday, April 12, 2019 For full credit, clear, legible, and correctly-rotated pages must be submitted to the correct location 1. (4 points) (Text 10.52) A gyroscope on the Moon. A certain gyroscope precesses at a rate of 0.500 rds when used on Earth. If it were taken to a lunar base, where the acceleration due to gravity is 0.165g, what would be its...
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
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