Company XYZ know that replacement times for the quartz time
pieces it produces are normally distributed with a mean of 13.7
years and a standard deviation of 0.8 years.
Find the probability that a randomly selected quartz time piece
will have a replacement time less than 11.8 years?
P(X < 11.8 years) =
X ~ N ( µ = 13.7 , σ = 0.8 )
P ( X < 11.8 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 11.8 - 13.7 ) / 0.8
Z = -2.375
P ( ( X - µ ) / σ ) < ( 11.8 - 13.7 ) / 0.8 )
P ( X < 11.8 ) = P ( Z < -2.375 )
P ( X < 11.8 ) = 0.0088
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 11 years and a standard deviation of 1.8 years. a) Find the probability that a randomly selected quartz time piece will have a replacement time less than 7.58 years? b) If the company wants to provide a warranty so that only 0.8% of the quartz time pieces will be replaced before the warranty expires, what is the time length of...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 15.4 years and a standard deviation of 1.4 years. Find the probability that a randomly selected quartz time piece will have a replacement time less than 12.6 years? P(X < 12.6 years) If the company wants to provide a warranty so that only 3.2% of the quartz time pieces will be replaced before the warranty expires, what is the time...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.8 years and a standard deviation of 0.9 years. Find the probability that a randomly selected quartz time piece will have a replacement time less than 8.6 years? P(X < 8.6 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
IN UUTUULLIS Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 16.3 years and a standard deviation of 1.1 years. Find the probability that a randomly selected quartz time piece will have a replacement time less than 14 years? P(X< 14 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact 2-scores or 2-scores rounded to 3 decimal places are accepted If the company wants...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 3.8% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 1.3% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...
Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 6.7 years and a standard deviation of 1.6 years. Find the probability that a randomly selected DVD player will have a replacement time less than 2.2 years? P(X < 2.2 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. If the company wants to provide a...
Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 9.7 years and a standard deviation of 2.1 years. Find the probability that a randomly selected DVD player will have a replacement time less than 5.9 years? P(X < 5.9 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. If the company wants to provide a...
Replacement times for televisions are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years. Find the probability that a randomly selected television will need a replacement time less than 6 years.
1.Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the population of potential clientele have head breadths that are normally distributed with a mean of 7-in and a standard deviation of 1.2-in. Due to financial constraints, the helmets will be designed to fit all men except those with head breadths that are in the smallest 1.2% or largest 1.2%. What is the minimum head breadth that will fit the clientele? min =...