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Find the value of z such that 62.9​% of the total area is to the left...

Find the value of z such that 62.9​% of the total area is to the left of z. LOADING... Click to view the areas under the Standard Normal Curve.

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Answer #1

Using standard normal table,

P(Z < z) = 0.629

P(Z < 0.33) = 0.629

z = 0.33

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