What is the component concentration ratio, [BrO−]/[HBrO], of a buffer that has a pH of 8.02?...

Question

Question

What is the component concentration ratio, [BrO⁻]/[HBrO], of a buffer that has a pH of 8.02?

(K_a of HBrO = 2.3 × 10⁻⁹)

science chemistry

Answer 1

Answer #1

Sol.

As Ka of HBrO = 2.3 × 10^-9

So , pKa = - log(Ka) = - log ( 2.3 × 10^-9 ) = 8.64

Using Henderson - Hasselbalch Equation ,

pH = pKa + log ( [BrO-] / [HBrO] )

8.02 = 8.64 + log ( [BrO-] / [HBrO] )

log ( [BrO-] / [HBrO] ) = 8.02 - 8.64 = - 0.62

[BrO-] / [HBrO] = 10^-0.62 = 0.2399

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Answer 2

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