Signed values: Convert each as indicated. You do not need to show your work. (But please do some explain,thanks)
If the answer must be a byte, then it must be the correct size.
in order to convert any number to the decimal form
the magnitude of the number *base of the number^{(position of the number)} additio of all possible spaces gives us the corresponding decimal number
for example
a.)
(86)_{16} is an hexadecimal number with base 16
now
8*16^{1}+6*16^{0}(this will give us the decimal)
=128+6=134 (unsigned)
now in order to see if the number is negative, we need a binary representation (is MSB is one for signed number the number is negative else it's positive
a signed number have n-1 number of bit since MSB defined the sign
now, 0x86 in binary=1000(8)0110(6)=10000110= -6 in decimal since MSB is 1 and magnitude is 6
now doing the same for part b.)
E9
unsigned 14*16^{1}+9*16^{0}=233
binary representation 1110(E)1001(9)=11101001= -105
now 1's complement
when a negative number is present all the bits of the number are inverted 0 to 1 and 1 to 0 respectively
1's complement for 86 hex
will be
an invert of signed binary 10000110
01111001 =121
for E9
an invert of signed binary11101001
00010110=22decimal
now for 2's complement adding 1 to the LSB of the 1's complement of a negative number gives the corresponding 2;s complement
for 86
01111001+00000001=01111010=122
for E9
00010110+00000001=00010111=23
for 0x14
binary 0001(1)0100(4)=00010100 since the number is not a negative number since MSB =0 no need for an 2's complement
representation.
Signed values: Convert each as indicated. You do not need to show your work. (But please...
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