1. Consider a process at 286 K with ΔH = -72.5 kJ/mol and ΔS =
-96.8 J/K mol
Which of the following is true?
ΔG = -44.8 kJ/mol and the process will not be spontaneous
ΔG = +39.4 kJ/mol and the process will be spontaneous
ΔG = -44.8 kJ/mol and the process will be spontaneous
ΔG = -19.1 kJ/mol and the process will not be spontaneous
ΔG = +39.4 kJ/mol and the process will not be spontaneous
2. Consider a process with ∆H = -89.8 kJ and ∆S = -151 J/K. At what temperature will this process be at equilibrium?
450
760
595
234
378
3. What does the standard change in Gibbs free energy (ΔG° ) of a reaction tell us about the equilbrium constant (K) for that reaction under standard conditions?
A negative ΔGº indicates that reactant formation is favored, and K will be less than 1.
There is no significant relationship between ΔG° and K
A negative ΔG° indicates that product formation is favored, and K will be greater than 1.
4.What is ΔSsurr (in J/K) if ΔHsys is -27.2 kJ and T is 379 K?
5. Which of the following processes have a ΔS that is positive? More then one answer
2 N2O5 (g) → 4 NO2 (g) + O2 (g)
CO2 (s) → CO2 (g)
H2O (l) → H2O(s)
N2 (g) → N2 (l)
Al (s) → Al (l)
1. Consider a process at 286 K with ΔH = -72.5 kJ/mol and ΔS = -96.8...
Consider a process at 286 K with ΔH = -72.5 kJ/mol and ΔS = -96.8 J/K mol Which of the following is true? ΔG = -19.1 kJ/mol and the process will not be spontaneous ΔG = -44.8 kJ/mol and the process will not be spontaneous ΔG = -44.8 kJ/mol and the process will be spontaneous ΔG = +39.4 kJ/mol and the process will not be spontaneous ΔG = +39.4 kJ/mol and the process will be spontaneous
A) If ΔH = -70.0 kJ and ΔS = -0.400 kJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins. B) Glacial acetic acid is the concentrated form of acetic acid, the acid in vinegar. The term "glacial" refers to the appearance of the solid form, which resembles ice-like crystals. What is the melting point of this compound, in degrees Celsius, based on its thermodynamic data shown here? ΔHfus (kJ/mol) ΔSfus...
A certain reaction has ΔH°= -19.5 kJ/mol and ΔS°= +42.7 J/mol K a) Is the reaction exothermic or endothermic? b) Does the reaction lead to an increase or decrease in the disorder of the system? c) Calculate ΔG° for the reaction at 298K. d) Is the reaction spontaneous at 298 K under standard conditions?
3) Answer all parts of the following question. a. The reaction: Al(s) + Fe2O3(s) → Fe(s) + Al2O3(s) has ΔH = -847.6 kJ and ΔS = -41.3 J/K at 25°C. Calculate ΔG and determine if it is spontaneous. b. Above what temperature does the following reaction become nonspontaneous? FeO(s) + CO(g) → CO2(g) + Fe(s) ΔH = -11.0 kJ; ΔS = -17.4 J/K c. Find ΔSsurr and predict whether or not this reaction will be spontaneous at 398 K. NH3(g)...
Consider a reaction for which ΔH = 6.03 kJ/mol; ΔS = 22.1 J/K-mol. Which of the following statements is true? a. The reaction becomes spontaneous at high temperatures above 273 K b. The reaction becomes spontaneous at low temperatures below 273 K c. The reaction is spontaneous at all temperatures d. The reaction is never spontaneous
For a particular reaction at 205.1205.1 °C, ΔG=−45.90 kJ/molΔG=−45.90 kJ/mol, and ΔS=395.61 J/(mol⋅K)ΔS=395.61 J/(mol⋅K). Calculate ΔG for this reaction at −6.1−6.1 °C.
Consider the following reaction at 298 K. C(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/KC(graphite)+2H2(g)⟶CH4(g)ΔH∘=−74.6 kJ and ΔS∘=−80.8 J/K Calculate the following quantities. ΔSsys=ΔSsys J/K ΔSsurr= J/K ΔSuniv= J/K
For the following reaction: 2 CO(g) + O2(g) → 2 CO2(g), given ΔH = -566 kJ and ΔG = -514 kJ, find ΔS (J/K) at 25 oC. Multiple Choices: ΔS = -174 J/K ΔS = -0.174 J/K ΔS = -2.08J/K ΔS = 174 J/K ΔS = -2080 J/K
Using the data: C2H4(g), = +51.9 kJ mol-1, S° = 219.8 J mol-1 K-1 CO2(g), = ‑394 kJ mol-1, S° = 213.6 J mol-1 K-1 H2O(l), = ‑286.0 kJ mol-1, S° = 69.96 J mol-1 K-1 O2(g), = 0.00 kJ mol-1, S° = 205 J mol-1 K-1 calculate the maximum amount of work that can be obtained, at 25.0 °C, from the process: C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(l)
1.) Calculate ΔHºrxn ΔSsurr and ΔSºrxn to determine if the reaction is spontaneous at 298 K ΔHºf : PCl3(g) = -287 kj/mol ΔSºf : PCl3(g) = -3112 J/mol *K ΔSºf : P4(s) = 41.1 J/mol*K ΔSºf : Cl2(g)= 2230 J/mol *K P4(s) +6Cl2(g) ------> 4PCl3(g) 2.) Calculate ΔGºrxn from enthalpy and entropy values at 298 K 4NH3 (g) +5O2(g) -----> 4 NO(g) +6H2O(g) ΔHºf : NO(g) = 90.29 kj/mol ΔHºf: H2O(g) = -241.826 kJ/mol ΔHºf: NH3(g) = -45.9 kJ/mol ΔSºf : NO(g)...