Calculate the pH of a solution that is 0.650 M HOCl and 1.10 M OCl-.
Ka of HOCl = 3.5*10^-8
pKa = - log (Ka)
= - log(3.5*10^-8)
= 7.456
use:
pH = pKa + log {[conjugate base]/[acid]}
= 7.456+ log {1.1/0.65}
= 7.684
Answer: 7.68
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