The mass of a star is 1.53·1031 kg and its angular velocity is 1.50E-7 rad/s. Find...
The mass of a star is 1.53·1031 kg and its angular velocity is 1.50E-7 rad/s. Find its new angular velocity if the diameter suddenly shrinks to 0.27 times its present size. Assume a uniform mass distribution before and after. Icm for a solid sphere of uniform density is 2/5 mr2.
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The mass of a star is 1.53·1031 kg and its angular
velocity is 1.50E-7 rad/s. Find...
star The mass of a star is 1.630×1031 kg and it performs one rotation in 28.30...
star The mass of a star is 1.630×1031 kg and it performs one rotation in 28.30 days. Find its new period (in days) if the diameter suddenly shrinks to 0.590 times its present size. Assume a uniform mass distribution before and after.
The mass of a star is 1.570×1031 kg and it performs one rotation in 27.70 days....
The mass of a star is 1.570×1031 kg and it performs one rotation in 27.70 days. Find its new period (in days) if the diameter suddenly shrinks to 0.830 times its present size. Assume a uniform mass distribution before and after.
The mass of a star is 1.770×1031 kg and it performs one rotation in 21.90 days....
The mass of a star is 1.770×1031 kg and it performs one rotation in 21.90 days. Find its new period (in days) if the diameter suddenly shrinks to 0.590 times its present size. Assume a uniform mass distribution before and after. A figure skater is spinning with an initial angular speed of 9.8rad/s. He then pulls his arms in, reducing his moment of inertia to 0.27 times its original value. What is his angular speed after pulling in his arms?...
1, A star with a mass of 1.25 × 1031 kg and a radius of 3.45...
1, A star with a mass of 1.25 × 1031 kg and a radius of 3.45 × 105 km is initially rotating on its axis with a period of 24.0 days. The star collapses and becomes a neutron star with a radius of 12.5 km, retaining all of its original mass. Assume the star is a uniform solid sphere before and after the collapse, with a moment of inertia given by (2/5)MR2. What is the period of rotation after collapse?...
The mass of a star is 1.030x1031 kg and it performs one rotation in 38.50 days....
The mass of a star is 1.030x1031 kg and it performs one rotation in 38.50 days. Find its new period (in days) if the diameter suddenly shrinks to 0.730 times its present size. Assume a uniform mass distribution before and after. Submit Answer Tries 0/12
A disk with radius 0.6 meters and mass 31 kg is spinning about its own center with an angular velocity of 88ed A solid sphere (/ mR2) with a radius of 0.18 meters which is spinning with an angula...
A disk with radius 0.6 meters and mass 31 kg is spinning about its own center with an angular velocity of 88ed A solid sphere (/ mR2) with a radius of 0.18 meters which is spinning with an angular velocity of -18 ed (the negative sign indicates the opposite 6. rad sec direction), is gently lowered onto the disk a sticks to the disk. The two rotate together (about their mutual center of mass) at an angular velocity of 33...
5*) Find the angular velocity of the Earth due to its daily rotation and express it...
5*) Find the angular velocity of the Earth due to its daily
rotation and express it in radians per second. Then use it, and a
model of the Earth as a solid sphere of mass M=
5.97 × 1024 kg and radius R
= 6.37 × 106 m, to estimate the angular momentum of the Earth due
to its rotation around its axis. (The result should be of the order
of 1033 kg m2/s. This is called the Earth’s “intrinsic”...
A 5.8 m diameter merry-go-round is rotating freely with an angular velocity of 0.50 rad/s. Its...
A 5.8 m diameter merry-go-round is rotating freely with an angular velocity of 0.50 rad/s. Its total moment of inertia is 2400 kg·m2. Four people standing on the ground, each of 65 kg mass, suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now?
A 3.9-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad/s . Its total...
A 3.9-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad/s . Its total moment of inertia is 1350 kg⋅m2 . Four people standing on the ground, each of mass 68 kg , suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now?
1.A solid uniform sphere of mass 3.7 kg and radius 0.051 m rotates with angular velocity...
1.A solid uniform sphere of mass 3.7 kg and radius 0.051 m rotates with angular velocity 7.3 rad/s about an axis through its center. Find the sphere’s rotational kinetic energy. 2.A certain pulley is a uniform disk of mass 2.7 kg and radius 0.25 m. A rope applies a constant torque to the pulley, which is free to rotate without friction, resulting in an angular acceleration of 0.12 rad/s2. The pulley starts at rest at time t = 0 s....
1, A star with a mass of 1.25 × 1031 kg and a radius of 3.45 × 105 km is initially rotating on its axis with a period of 24.0 days. The star collapses and becomes a neutron star with a radius of 12.5 km, retaining all of its original mass. Assume the star is a uniform solid sphere before and after the collapse, with a moment of inertia given by (2/5)MR2. What is the period of rotation after collapse?...
The mass of a star is 1.030x1031 kg and it performs one rotation in 38.50 days. Find its new period (in days) if the diameter suddenly shrinks to 0.730 times its present size. Assume a uniform mass distribution before and after. Submit Answer Tries 0/12
A disk with radius 0.6 meters and mass 31 kg is spinning about its own center with an angular velocity of 88ed A solid sphere (/ mR2) with a radius of 0.18 meters which is spinning with an angular velocity of -18 ed (the negative sign indicates the opposite 6. rad sec direction), is gently lowered onto the disk a sticks to the disk. The two rotate together (about their mutual center of mass) at an angular velocity of 33...
5*) Find the angular velocity of the Earth due to its daily
rotation and express it in radians per second. Then use it, and a
model of the Earth as a solid sphere of mass M=
5.97 × 1024 kg and radius R
= 6.37 × 106 m, to estimate the angular momentum of the Earth due
to its rotation around its axis. (The result should be of the order
of 1033 kg m2/s. This is called the Earth’s “intrinsic”...
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