(As soon as possible) Balance each of the following equations according to the half-reaction method: H2O2(aq) + MnO4−(aq)⟶Mn2+(aq) + O2(g) (in acid)
| 5H2O2(aq) + MnO4−(aq) + 6H3O+(aq) ⟶ Mn2+(aq) + 5O2(g) + 14H2O(l) | |
| 5H2O2(aq) + 2MnO4−(aq) + 6H3O+(aq) ⟶ 2Mn2+(aq) + 5O2(g) + 14H2O(l) | |
| 5H2O2(aq) + 2MnO4−(aq) + 7H3O+(aq) ⟶ Mn2+(aq) + 5O2(g) + 15H2O(l) |
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(As soon as possible) Balance each of the following equations according to the half-reaction method: H2O2(aq)...
The redox reaction between hydrogen peroxide, H2O2, and permanganate ions, MnO4-, in acid solution are as follows: 5H2O2(aq) + 2MnO4-(aq) + 6H+(aq) → 5O2(g) + 2Mn2+(aq) + 8H2O (l) 5 mol of MnO4-was required to reach the equilibrium. How many moles of H2O2were required to reach the equilibrium? a) 2 mol b. 10 mol c) 12.5 mol d) 25 mol
A permanganate solution is standardized by titrating it with a 0.1491 M hydrogen peroxide solution. The balanced net ionic equation for the reaction is: 2MnO4-(aq) + 5H2O2(aq)+6H3O+(aq)2Mn2+(aq) + 5O2(g)+14H2O(l) If 21.22 mL of the 0.1491 M hydrogen peroxide solution is required to react completely with 25.00 mL of the permanganate solution, calculate the concentration of the permanganate solution.
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): BrO3 – + Cr3+ → Br2 + HCrO4 – (b) (acid solution): MnO4 – + VO2+ → Mn2+ + V(OH)4 + (c) (basic solution): MnO4 – + OH– → MnO4 2– + O2 (g)
Balance the following redox equations by the half-reaction method: (a) Mn2+ + H2O2 → MnO2 + H2O (in basic solution) (b) Bi(OH)3 + SnO22− → SnO32− + Bi (in basic solution) (c) Cr2O72− + C2O42− → Cr3+ + CO2 (in acidic solution) (d) ClO3− + Cl− → Cl2 + ClO2 (in acidic solution) (e) Mn2+ + BiO3− → Bi3+ + MnO4− (in acidic solution)
Balance the following redox reaction: H2O2(aq) + MnO4-(aq) ↔ O2(g) + Mn2+(aq)
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Balance each of the following equations according to the half-reaction method: 1) CN- (aq) + ClO2( aq) —> CNO- (aq) + Cl- (aq) (in acid) 2) MnO4- (aq) +NO2- (aq) → MnO2( s) + NO3 - (aq) (in base) 3) In which species does nitrogen have the highest oxidation number? a) NaNO3 b) HNO2 c) NO2- d) NH3 e) N2
a Choose the balanced equation for the following half-reaction, which takes place in acidic solution MnO4 (aq)Se2 (aq) -> Mn2(aq) Se(s) O 16H (aq)2Mn04- (aq)5Se2 (aq) ->2Mn2 (aq) 6H20()5Se(s) O16H (aq)2MnO4- (aq)5Se2 (aq) -2Mn2 (aq) 8H20(1) 5Se(s) 16H+ (aq)MnO4 (aq) 5Se2(aq) - Mn2(aq) +8H20(l) 5Se(s) O16H (aq)MnO4- (aq) 5Se2 (aq) -2Mn2(aq) + 8H2O(l)5Se(s) bChoose the balanced equation for the following half-reaction, which takes place in acidic solution: S2Os2(aq)CI (aq) SO42(aq) Cl2 (aq) S2O82(aq)2CI (aq) 2SO42(aq) Cl2(aq) S2O82-(aq)C (aq) -2SO42-(aq) 2Cl2...
Use the half-reaction method to balance each redox reaction occurring in acidic aqueous solution. Cl−(aq)+MnO4−(aq)→Cl2(g)+Mn2+(aq) Express your answer as a chemical equation. Identify all of the phases in your answer.
2. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO (s) + PbO2 (s) → MnO,- + Pb2+ (b) (acid solution): MnO4 + Mn2+ → MnO2 (s) (c) (basic solution): Al (8) + OH → Al(OH) - + H2(g)