Assume Kw = 1.01 ✕ 10−14 For pure water, we can calculate [H3O+ ] = [OH...

Question

Question

Assume Kw = 1.01 ✕ 10−14

For pure water, we can calculate [H3O+ ] = [OH − ] = ____ M.

(a) 7 ✕ 10−8 M HNO3.....The [H3O+ ]added (in M) derived from HNO3 is _____ M.

(b) 0.54 g HCl in 1.0 L of solution......The [H3O+ ]added (in M) derived from HCl is ____ M.

(c) 0.00070 g NaOH in 0.50 L of solution.....The [OH − ]added (in M) derived from NaOH is ____ M.

(d) 5 ✕ 10−7 M Ca(OH)2.....The [OH − ]added (in M) derived from Ca(OH)2 is ____ M.

(e) 0.0265 M KNO3.....The [OH − ]added (in M) derived from KNO3 is ____ M.

science chemistry

Answer 1

Answer #1

Answer 2

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