How many milliliters of 10.5 M hydrobromic acid solution should be used to prepare 2.00 L of 0.800 M HBr ?
By the formula,
N1 X V1 = N2 X V2
we can also use Molarity(M) in place of Normality (N),
M1 X V1 = M2 X V2
10.5 M X V1 = 0.8 M X 2 Liters
V1 = 0.8 X 2 X 1000/ 10.5 mL
V1= 152.38 mL of 10.5 M hydrobromic acid should be used.
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