Question

Population Standard Deviation 5.0000 Sample Size 11 Sample Mean 54.9091 Confidence Interval Confidence Coefficient 0.98 Lower...

Population Standard Deviation 5.0000
Sample Size 11
Sample Mean 54.9091
Confidence Interval
Confidence Coefficient 0.98
Lower Limit
Upper Limit
Hypothesis Test
Hypothesized Value 50
Test Statistic
P-value (Lower Tail)
P-value (Upper Tail)
P-value (Two Tail) 0.0012
Sample Size 11
Sample Mean 54.9091
      Sample Standard Deviation 5.5759
Confidence Interval
Confidence Coefficient 0.98
Lower Limit
Upper Limit
Hypothesis Test
Hypothesized Value 50
Test Statistic
P-value (Lower Tail)
P-value (Upper Tail)
P-value (Two Tail) 0.0154

Studies show that massage therapy has a variety of health benefits. Eleven typical one-hour massage therapy sessions were randomly selected, the amount charged for those sessions recorded, and this information put into Excel. Does the data suggest that the average charge for a typical one-hour massage therapy session is greater than $50 at α=.01? Based on this paragraph of text, use the correct excel output above to answer the following question.

For the hypothesis stated above, what is the P-value?

a.

0.9923

b.

0.0006

c.

None of the answers is correct

d.

0.0077

e.

0.0154

0 0
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Answer #1

Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (54.9091 - 50)/(5/sqrt(11))
z = 3.256

P-value Approach
P-value = 0.0006

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