A 4.298 g sample of the mineral tellurite (TeO2) was dissolved in acid. A 50.00 mL volume of a 0.02842 M K2Cr2O7 solution was added.
3 TeO2 s+ Cr2O72- aq+8 H+ aq3 H2TeO4 aq+2 Cr3+ aq+H2O l
When the reaction is complete, the excess Cr2O72– is back-titrated, requiring 13.76 mL of 0.1062 M Fe2+ to reach the end point.
a) Use appropriate half-reactions to write the balanced reaction equation for the back-titration of the excess Cr2O72– with Fe2+. (3 pts)
b) Determine the %TeO2 in the mineral sample. (5 pts)
A 4.298 g sample of the mineral tellurite (TeO2) was dissolved in acid. A 50.00 mL...
4. A 0.5255 g sample containing an unknown mass of SnCl2 is dissolved in 50.00 mL of water and titrated with 0.02050 M KMnO4 under mildly acidic conditions. The unbalanced titration reaction is shown below. MnO4 (aq) + Sn²(aq) MnO2(8) + Sn** (aq) a. Use the half-reaction method to balance the titration reaction. (5 pts) b. Given that 32.25 mL of KMnO, was required to reach the endpoint, calculate the percent SnCl2 in the sample. (5 pts)
A 50.0 g sample of ore containing FeBr2 is dissolved in acid and titrated to an end point with 24.80 mL of 0.629 M Cr2O72−. The following redox reaction takes place: Cr2O72− (aq) + Fe2+ (aq) ⟶ Cr3+ (aq) + Fe3+ (aq) a. balance the reaction b. what % of the ore sample if FeBr2 (molar mass = 215.65 g/mol)
The Fe2+ (55.845 g/mol) content of a 2.264 g steel sample dissolved in 50.00 mL of an acidic solution was determined by tiration with a standardized 0.120 M potassium permanganate (KMnO4, 158.034 g/mol) solution. The titration required 44.82 mL to reach the end point. What is the concentration of iron in the steel sample? Express your answer as grams of Fe per gram of steel Mn2+5 Fe34 H20 + 5 Fe2+ MnO8 H concentration g Fe/g steel A 1.969 g...
• CIU TEXAS INSTRUM 2. A 50.00 ml sample of solution containing Fe?ions is titrated with a 0.0216 M KMnO4 solution. It required 20.62 ml of the KMnO4 solution to oxidize all the Fe? ions to Fe ions by the reaction: MnO4 (aq) + Fe? ) -------> Mn(ed) Felco (unbalanced) a) What was the concentration of Fel.ions in the sample solution? b) What volume of 0.0150 M K2Cr2O7 solution would it take to do the same titration? The reaction is:...
A sample of iron ore weighing 0.6428g is dissolved in acid, the iron is reduced to Fe2+, and the solution is titrated with 36.30 mL of 0.01753 M K2Cr2O7 solution. The reaction is 6Fe2+ + Cr2O72- +14H+ à 6Fe3+ + 2Cr3+ + 7H2O What is the Percentage of iron (55.85g/mol) in the sample?
The Fe2+ (55.845 g/mol) content of a 2.370 g steel sample dissolved in 50.00 mL was determined by tiration with a standardized 0.120 M potassium permanganate (KMnO4, 158.034 g/mol) solution. The titration required 39.51 mL to reach the end point. What is the concentration of iron in the steel sample? Express your answer as grams of Fe per grams of steel (g Fe2+1 g steel). Mno, +8H+ + 5Fe2+ = Mn2+ + 5Fe'+ + 4H,0 Number g Fe2+1 g steel
An unknown solution was analyzed for Ni by an EDTA titration. A 50.00 mL sample of the unknown was treated with 25.00 mL of 0.2404 M EDTA. The excess EDTA was then back titrated with 8.52 mL of 0.0694 M Zn2+ to reach the equivalence point. What was the concentration of Ni (in unit of M) in the 50.00 mL sample? Please keep your answer to three decimal places.
A 0.200 g sample of an unknown monoprotic acid (e.g., HX) is dissolved in water and titrated with NaOH. The equivalence point of the titration is reached after the addition of 19.03 mL of 0.1750 M NaOH. Calculate the molar mass of the acid. NaOH(aq) + HX(aq) → H2O(l) + NaX(aq) (Balanced)
4. A 2.86 g sample containing both Fe and V was dissolved under certain conditions and diluted to 200.00 mL. Fe2 and VO ions. The titration of this solution required 22.64 mL of0.1000 M Ce" to reach end point. A second 50.00 mL aliquot was passed through a Jones reductor to forn ions. The titration of the second solution required 42.66 mL of 0.1000 M Ce solution to reach an end point. Calculate the percentage of Fe and V in...
A 250.0 mL sample of spring water was treated to convert any iron present to Fe2+ . Addition of 24.00 mL of 0.002543 M K2Cr2O7 resulted in the reaction 6Fe2+ + Cr2O7 2- + 14H+ 6Fe3+ + 2Cr3+ + 7H2O The excess K2Cr2O7 was back titrated with 8.02 mL of 0.00971 M Fe2+ solution. Calculate the concentration of iron in the sample in ppm. Please be specific and include details.