The speed of cars on the Laurentian Autoroute are known to form a normal distribution with u=105 km/hr and o= 10 km/hr. If a car was randomly selected, what is the probability that its speed was between 95 and 110 km/hr? Express your answer as a percentage (rounder to two decimal places)
Solution :
Given that ,
mean =
= 105
standard deviation =
= 10
P(95 < x < 110) = P((95 - 105)/ 10) < (x -
) /
< (110 - 105) / 10) )
= P(-1 < z < 0.5)
= P(z < 0.5) - P(z < -1)
= 0.6915 - 0.1587
= 0.5328
= 53.28%
Probability = 53.28 %
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