Question

1. Consider the following reaction where Kc = 1.20×10-2at 500 K: PCl5(g) ------ PCl3(g) + Cl2(g)...

1. Consider the following reaction where Kc = 1.20×10-2at 500 K:

PCl5(g) ------ PCl3(g) + Cl2(g)

A reaction mixture was found to contain 0.136 moles of PCl5(g), 2.47×10-2moles ofPCl3(g), and 4.45×10-2moles of Cl2(g), in a 1.00 liter container.

Indicate True (T) or False (F) for each of the following:

___TF 1. In order to reach equilibrium PCl5(g) must be produced .
___TF 2. In order to reach equilibrium Kc must decrease .
___TF 3. In order to reach equilibrium PCl3must be produced .
___TF 4. Qc is less than Kc.
___TF 5. The reaction is at equilibrium. No further reaction will occur.

2. Consider the following reaction where Kc = 83.3 at 500 K:  

PCl3(g) + Cl2(g) -------PCl5(g)  

A reaction mixture was found to contain 2.20×10-2 moles of PCl3(g), 4.31×10-2 moles of Cl2(g) and 0.110 moles of PCl5(g), in a 1.00 Liter container.

Indicate True (T) or False (F) for each of the following:

___TF 1. In order to reach equilibrium PCl5(g) must be consumed.
___TF 2. In order to reach equilibrium Kc must decrease.
___TF 3. In order to reach equilibrium PCl3 must be produced.
___TF 4. Qc is greater than Kc.
___TF 5. The reaction is at equilibrium. No further reaction will occur.

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