Question

The de Broglie wavelength of a 0.0600 gram bullet traveling at the speed of 655.5 m/s is ________ m.

is the answer:

a. 1.685×10⁻³⁵

b. 1.685×10⁻³³

c. 2.606×10⁻³⁵

d. 1.685×10⁻³²

e. 1.685×10⁻³⁴

Answer 1

By using formula,

λ = h/p

    where λ is wavelength,

               h is Planck constant,

    λ = h/mv

      = 6.626*10^-34 / (6*10^-5) *(655.5)

      = = 1.685*10^-32 m