Question

*Answer must be in C*

Write a program that:

1- Declare and initialize all values to zero an array of doubles 10 x 10 named "cat"

2- Write the code(using for loops) to fill the array with values 1, 2, 3, .... 98, 99, 100

3- Output (using for loops) the sum of the diagonal from 1-100

4- Output (using for loops) the sum of the last 50 rows of the array

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: The last question (the sum of the last 50 rows of the array) is confusing. There are only 10 rows in the array, so I meant last 5 rows (second half) instead of 50. Also assuming you meant the sum of all elements in all those rows, instead of finding sum row by row separately. So if this is anything different than what I understood, please let me know in comments, I’ll correct it as soon as I can.

#include<stdio.h>

int main(){

                //creating a 10x10 array initialized with 0s

                int cat[10][10]={0};

               

                int value=1;

                //looping through each row

                for(int i=0;i<10;i++){

                                //looping through each column

                                for(int j=0;j<10;j++){

                                               //setting value to element at row i and column j

                                               cat[i][j]=value;

                                               //incrementing value

                                               value++;

                                }

                }

               

                //initializing sum of diagonals to 0

                int sumDiagonal=0;

                //looping from i=0 to i=9

                for(int i=0;i<10;i++){

                                //adding element at row i, column i to sumDiagonal

                                //note: indices of diagonal goes from (0,0), (1,1), (2,2) etc.. upto (9,9)

                                sumDiagonal+=cat[i][i];

                }

                //printing sum of diagonal

                printf("sum of diagonal from 1-100 = %d\n",sumDiagonal);

                               

                //now, in the question it says to compute the sum of last 50 rows. but there are no

                //50 rows, the array has 10 rows and 10 columns only. so i'm assuming that you meant

                //last 5 rows (second half) instead of 50 rows

                int sumLast5rows=0;

               

                //starting from 6th row to 10th row, finding sum of all values

                for(int i=5;i<10;i++){

                                for(int j=0;j<10;j++){

                                               sumLast5rows += cat[i][j];

                                }

                }

                //printing sum

                printf("sum of all elements in last 5 rows = %d\n",sumLast5rows);

                return 0;

}

/*OUTPUT*/

sum of diagonal from 1-100 = 505

sum of all elements in last 5 rows = 3775