Part A Part complete What is the magnitude of the electric field? E = 559 V/m...
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Part A Part complete What is the magnitude of the electric field?
SubmitPrevious Answers Correct Part B Part complete What is the direction of the electric field?
SubmitPrevious Answers Correct Part C What is the shortest distance one can move to undergo a change in potential of 2.00 V ?
SubmitPrevious AnswersRequest Answer Incorrect; Try Again; One attempt remaining |
Homework Answers
(C) We have the relation:
E = V/d
Rearranging in terms of d, we get:
d = V/E
= 2/559
= 3.58e-3 m
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Part A
Part complete
What is the magnitude of the electric field?
E =
559
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At a distance of 12 mm from a charged particle, the electric
field has a magnitude of 100 N/CN/C.
Part A
At what distance is the electric field 400 N/CN/C?
Express your answer with the appropriate units.
r1r1 =
SubmitPrevious AnswersRequest Answer
Incorrect; Try Again; 5 attempts remaining
Part B
At what distance is it 16 N/CN/C?
Express your answer with the appropriate units.
r2r2 =
nothingnothing
SubmitRequest Answer
Provide Feedback
Next
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